Quantity A Quantity B
Total number of different values of “p” 2

A. Quantity A is greater. 

B. Quantity B is greater. 

C. The two quantities are equal. 

D. The relationship cannot be determined from the information given.

Answer: A 

Explanation:

Trap answer: C- Both the quantities are equal

Nature of trap: Eliminating common variables on both the sides of the equation (Zero trap).

Rule: Never cancel common variables on both the sides of the equation. Because zero could be one of the solutions. If question mentions that variable cannot be equal to zero, then we can cancel that common variable.

p^3+10p^2-5p^2+6p=0
p(p^2+5p+6=0)

So, p could be 0, -2 and-3

There are three different values of “p”

So, Quantity A is greater than Quantity B.

Hence the answer is A.

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